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Notes

[1] One implication of this requirement is that a const type is not Assignable. For example, const int is not Assignable: if x is declared to be of type const int, then x = 7 is illegal. Similarly, the type pair is not Assignable.

[2] The reason this says "x is a copy of y ", rather than "x == y ", is that operator== is not necessarily defined: equality is not a requirement of Assignable. If the type X is EqualityComparable as well as Assignable, then a copy of x should compare equal to x.


Expression semantics | Standard Template Library Programmer`s Guide | Default Constructible







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